Here is a simple logical puzzle. Some magicians use this to give example of illusion. This is how the story goes.
There was a shephard who had a flock of sheep. He appointed a wolf to guard them. The sheeps were flocked in exact tens around a pit. Every evening the shepard would count his sheeps in the way shown below before retiring for the night. This was easier to keep track as he knew counting only till ten.
The wolf was smart and was aware of the shepards weakness. The first day he eat one sheep and re-arranged them. The shepard as usual counted the sheeps at the end of the day and didnt come to know of the missing sheep.
The next day the wolf's greed increased. Now he eat two sheeps from the herd and again re-arranged them in such a way that each group had exactly ten sheeps.
Any idea how the wolf did it. Here is how it was done. If you want you can do it simultaneously and see the magic for yourself.
1. On the first day he eat the sheep from this position.
2. Then he moved the sheep from the position shown below to the new position.
3. This is how it looked after a sheep was eaten.
4. The shephard came in the evening and counted the sheeps.
Here there were ten sheeps like the previous day.
5. The next day the greedy wolf ate two sheeps this time from these positions.
6. He then moved the sheeps to their new positions as shown below.
7. Once again in the evening the shephard counted them all and there he had ten sheeps in each of the groups as the previous day.
This is how the three sheeps were slaughtered and the wolf retained his job as well. ;)
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